(a) Parameterize the circle (x + 3)^2 + y^2 = 4. (b) Parameterize the curve which is the intersection of the plane 2x + 4y + z = 4 with the surface z = x^2 + y^2. Hint: eliminate z.
Added by Jacob E.
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Therefore, the parametrization is given by: \[ \textbf{x = -3 + 2\cos(\theta)} \] \[ \textbf{y = 2\sin(\theta)} \] where \( \theta \) belongs to the closed interval [0, 2\(\pi\)]. Show more…
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