A particle executing SHM has amplitude of 4 cm and its acceleration at a distance of 1 cm from the mean position is 3 cm s?². What will be its velocity be when it is at a distance of 2 cm from its mean position?
Added by Arun B.
Step 1
Plugging in the values, we get \( 3 = -\omega^2(1) \). Show more…
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