00:01
So, given that v dv upon dt is equal to t square plus 4t plus 3 because at is the acceleration and acceleration is equal to velocity.
00:14
So, upon time so there is dv upon dt is equal to t square plus 4t plus 3.
00:20
So, the integration of 15 to v dv is equal to integration of 0 to t, t square plus 4t plus 3 dt.
00:33
This is the function after integration we have minus v minus 15 is equal to t cube upon 3 plus 4t square upon 2 plus 3t.
00:45
So, v is equal to t cube upon 3 plus 2t square plus 3t plus 15.
00:55
So, v is equal to ds upon dt is equal to t cube upon 3 plus 2t square plus 3t plus 15.
01:08
So, the integration of 0 to s ds is equal to integration of 0 to t, t cube upon 3 plus 2t square plus 3t plus 15 dt.
01:26
So, there is s is equal to t square upon 12 plus 2t cube upon 3 plus 3t square upon 2 plus 15t...