A particle moves along a straight line according to the equation x(t) = t^3 - 6t^2 + 5, where x is in meters and t is in seconds. Find the total distance traveled by the particle after 6 seconds.
Added by Jennifer C.
Step 1
So, we have: v(t) = \frac{dx(t)}{dt} = \frac{d(t^3 - 6t^2 + 5)}{dt} Now, we can find the derivative: v(t) = 3t^2 - 12t Show more…
Show all steps
Close
Your feedback will help us improve your experience
Khushbu Rani and 91 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle moves along a coordinate line and s, its directed distance in centimeters from the origin after t seconds, is given by s = f(t) = √(6t + 5). Find the instantaneous velocity of the particle after 3 seconds.
Zhumagali S.
A particle moves along a straight line so that its position at time t seconds is x(t ) metres,relative to the origin. Assume that x(0) = 0, x(3) = 3 and x(6) = - 6, and that the particleonly changes direction when t = 3. Find the distance travelled by the particle from time t = 0 to time t = 6.
Suman Saurav T.
The displacement of a particle moving in a straight line is described by the relation, s = 6 + 12t – 2t2. Here’s is in meters and t in seconds. The distance covered by particle in first 5 s is:
Dharmendra M.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
600,000+
Students learning Calculus with Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD