00:01
For part a, we'd like to find the displacement.
00:03
To find our displacement, we can use our expression, our equation of motion, to find s equal to v squared minus u squared over 2a.
00:13
So we want to divide our final velocity, 14 squared minus 7 squared divided by 2 times 3 .25.
00:23
And this will give us our displacement.
00:26
So let's plug that into a calculator.
00:28
14 squared minus 7 squared divided by 2 times 3 .25 gives us 22 .6 meters as our displacement.
00:40
Now for part b, what is the distance it travels during this interval? the distance is the same.
00:49
It is still 22 .6 meters.
00:53
For c, it has the same constant acceleration, and its velocity is the same constant acceleration...