Question

A particle of mass $1.00 \mathrm{~kg}$ is moving with velocity $\vec{v}=(7.0 \mathrm{i}+6.0 \mathrm{j}) \mathrm{m} / \mathrm{s} . \quad(a)$ Find the angular momentum 1. relative to the origin when the particle is at $\overrightarrow{\mathbf{r}}=(2.0 \mathbf{j}+4.0 \mathbf{k}) \mathrm{m}$ (b) At position $\overrightarrow{\mathbf{r}}$ a force of $\mathbf{F}=4.0 \mathrm{Ni}$ is applied to the particle. Find the torque relative to the origin.

Name: a particle of mass 100 mathrmkg is moving with velocity vecv70 mathrmi60 mathrmj mathrmm mathrms quada find the angular momentum 1 relative to the origin when the particle is at overrightarrowmathbf 2
Uploaded: 2021-08-18T06:56:52-08:00
Duration: 3 min 48 s
Channel: Pritesh Ranjan
Description: a particle of mass 100 mathrmkg is moving with velocity vecv70 mathrmi60 mathrmj mathrmm mathrms quada find the angular momentum 1 relative to the origin when the particle is at overrightarrowmathbf 2

          A particle of mass $1.00 \mathrm{~kg}$ is moving with velocity $\vec{v}=(7.0 \mathrm{i}+6.0 \mathrm{j}) \mathrm{m} / \mathrm{s} . \quad(a)$ Find the angular momentum
1. relative to the origin when the particle is at $\overrightarrow{\mathbf{r}}=(2.0 \mathbf{j}+4.0 \mathbf{k}) \mathrm{m}$
(b) At position $\overrightarrow{\mathbf{r}}$ a force of $\mathbf{F}=4.0 \mathrm{Ni}$ is applied to the particle. Find the torque relative to the origin.

Added by Patrick S.

Physics for Scientists and Engineers with Modern Physics

Douglas C. Giancoli 4th Edition

Chapter 11

Instant Answer

Solved by Expert Pritesh Ranjan

08/18/2021

Step 1

Given: Mass, $m = 1.00 \text{ kg}$ Velocity, $\vec{v} = 7.0\hat{i} + 6.0\hat{j} \text{ m/s}$ Position vector, $\vec{r} = 2\hat{j} + 4\hat{k} \text{ m}$ Linear momentum, $\vec{p} = m\vec{v} = 1.00(7.0\hat{i} + 6.0\hat{j}) = 7.0\hat{i} + 6.0\hat{j}$ Angular Show more…

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A particle of mass $1.00 \mathrm{~kg}$ is moving with velocity $\vec{v}=(7.0 \mathrm{i}+6.0 \mathrm{j}) \mathrm{m} / \mathrm{s} . \quad(a)$ Find the angular momentum 1. relative to the origin when the particle is at $\overrightarrow{\mathbf{r}}=(2.0 \mathbf{j}+4.0 \mathbf{k}) \mathrm{m}$ (b) At position $\overrightarrow{\mathbf{r}}$ a force of $\mathbf{F}=4.0 \mathrm{Ni}$ is applied to the particle. Find the torque relative to the origin.