a period of oscillation of a compound pendulum when suspended at a distance of 35 cm from 1 and is found to be 2.36 seconds what will be the length of equivalent simple pendulum having the same.
Added by Jared W.
Step 1
The period of a compound pendulum is given by the formula: T = 2π√(I/mgh) Where: T = period of oscillation I = moment of inertia of the compound pendulum m = mass of the compound pendulum g = acceleration due to gravity h = distance from the center of mass to Show more…
Show all steps
Your feedback will help us improve your experience
Abhinaw Raj and 70 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A Pendulum Of Length 45.3 Cm Is Hanging From The Ceiling. What Is The Period Of Oscillation?
Abhinaw R.
A simple pendulum oscillates with a period of $3.5 \mathrm{s}$. What is its length?
Harmonic Motion and Elasticity
Examples of Simple Harmonic Motion
The time taken for 50 oscillations of a simple pendulum is 45.5 s. If the acceleration due to gravity is 9.81 ms-2. Calculate. [Ans: T = 0.91 s; l = 0.21 m]. i. The period ii. The length of the simple pendulum.
Adi S.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD