A person draws a card from a pack of playing cards, replaces it and shuffles the pack. He continues doing this until he shows a spade. The chance that he will fail the first two times is (A) \( \frac{9}{16} \) (B) \( \frac{3}{14} \) (C) \( \frac{3}{5} \) (D) \( \frac{2}{9} \)
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A standard deck has 52 cards, with 13 spades. Therefore, the probability of not drawing a spade is: \[ P(\text{not a spade}) = \frac{52 - 13}{52} = \frac{39}{52} = \frac{3}{4} \] Show more…
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A person draws a card from a pack of 52 playing cards, replaces it and shuffles the pack. He continues doing this until be draws a spade, the chance that he will fail in the first two draws is (A) $\frac{1}{16}$ (B) $\frac{9}{16}$ (C) $\frac{9}{64}$ (D) $\frac{1}{64}$
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