A piece of steel (8050 kg/m3) is full submerged in water (1000 kg/m3). If the steel has a volume of 1.00 m3, then what is the buoyant force?
Added by Miguel F.
Step 1
The volume of the water displaced is equal to the volume of the steel, which is 1.00 m3. The weight of the water displaced can be calculated using the formula: Weight = Density * Volume * g where g is the acceleration due to gravity (approximately 9.81 Show more…
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