00:01
Hello swans, in this question width of the plate is given as 100 mm, thickness of the plate is given as 10 mm, p is equal to 70 kn and sigma is equal to 70 mpa which is equal to 70 into 10 to the power of 3 kpa.
00:26
You know that for fillet weld starting and stopping length of the weld run l1 will be equal to 12 .5 mm and the strength of fillet weld for static load is given by the formula sigma is equal to 1 .414 into s into l into p.
01:19
So here l is the length of the weld and s is the size of the weld which is equal to plate thickness.
01:39
Substituting we get l is equal to sigma divided by 1 .414 into s into p.
01:50
So this will be equal to 70 into 10 to the power of 3 divided by 1 .414 into 10 into 70.
02:01
So l will be equal to 70 .72 mm.
02:09
The final size of the weld lf is equal to l plus l1.
02:22
Substituting the value of l and l1 we get 70 .72 plus 12 .5.
02:32
So the final size of the weld for static load will be equal to 83 .2 mm...