a point charge of +2.4uC is located at the origin of a coordinate system and a second point charge of -6.4uC is at x=1.7 m what is the electric potential at x=0.85m point
Added by Andrea R.
Step 1
4 μC = +2.4×10^-6 C (at x = 0), q2 = -6.4 μC = -6.4×10^-6 C (at x = 1.7 m). Point of interest: x = 0.85 m. Show more…
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