00:01
Let's say v perpendicular is the component of the velocity that is perpendicular to the magnetic field.
00:14
And v parallel is the component which is parallel to the magnetic field.
00:20
Now we know solving for part a, we know that the lawrence force, the magnetic force on a moving charge particle acts only on the perpendicular component.
00:33
There is no force acting on the parallel component.
00:37
Now the force on the perpendicular component of the velocity of electron can be written as qvb.
00:46
And from here we can find the perpendicular component of positron's velocity.
00:55
V perpendicular will be equals to fb by qb.
01:00
Substituting the values as given in the cussion, the value of magnetic force is given 1 .6 .00 into 10 to the power minus 12 newtons divided by the charge in the positron, which is nothing but the electronic charge, 1 .6 into 10 to the power minus 19 times the magnetic field 0 .510 tesla's.
01:30
Following this, we will get 1 .5 .1 .10.
01:35
961 into 10 to the power 7 meter per second.
01:41
This is the final answer for part a.
01:47
For solving part b, we know that the magnitude of the total magnetic field vector is given to equals to, sorry, the magnitude of the velocity vector is given to be equals to 4 .00 into the magnitude of the velocity vector is given to be equals to 4 .000 into.
02:07
10 to the power 7 meter per second.
02:11
Therefore, the sum of v perpendicular square and v parallel square will be is equal to 4 .00 into 10 to the power 7 meter per second.
02:30
Now we know v perpendicular, we will take it to another side...