00:01
Hello students here magnetic field f is b is given as 0 .47 tesla and magnetic force f is equals to 2 .3 into 10 power minus 12 neutons and it is given that velocity is equals to 5 .0 into 10 power minus it is equal to 7 meter per second and it is given that charge is equal to proton which is equal to 1 .6.
00:30
Into 10 power minus 19 column.
00:34
We know that the relation f is equal to q into v b sine theta.
00:41
We need to calculate the values of it is equal to the value of velocity of perpendicular.
00:50
Therefore velocity of perpendicular can be given as v perpendicular is equal to the value of here v into sine theta and v parallel can be given as parallel can be given as v into cos theta here for perpendicular velocity and component velocity and to find the v perpendicular we need to calculate the value of theta therefore f is equals to k u b sine theta therefore, sine theta can be given as f by qvb, which is equal to the value of here, it is given that sine theta equal to f is equal to it is the value of 2 .3 into 10 power minus 12 divided by q equal to 1 .6 into 10 power minus 19 and v is given as the value of 5 into 10 power 7 and b is given as the value of 5 into 10 power 7 and b is given.
02:06
Given as 0 .47 tesla, therefore, sine theta equal to the value of 0 .611, therefore, theta equals to sine inverse of 0 .611, therefore, theta equal to the value of, here it is 37 .66 degrees...