A projectile is fired straight upward at ( 141 frac{mathrm{m}}{mathrm{s}} ). (a) How fast is it moving upward at the instant it reaches the top of its trajectory? (b) Suppose instead it were fired upward at ( 45^{circ} ). What would be its speed at the top of its trajectory?
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This is because at the top of its trajectory, the projectile momentarily stops moving upward before it starts to fall back down. So, the speed of the projectile at the top of its trajectory is 0 m/s. (b) When a projectile is fired at an angle, its velocity at the Show more…
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A projectile is fired straight upward at 141 $\mathrm{m} / \mathrm{s}$ . How fast is it moving at the instant it reaches the top of its trajectory? Suppose that it were fired upward at $45^{\circ}$ instead. Then its horizontal component of velocity would be 100 $\mathrm{m} / \mathrm{s}$ . What would be the speed of the projectile at the top of its trajectory?
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