A projectile is launched on level ground. At the peak of its trajectory, it is 7.5 meters high. Itlands 10 meters from where it was launched. At what angle was the projectile launched?
Added by Allen N.
Step 1
First, we need to find the time it takes for the projectile to reach its peak height. We can use the following equation for vertical motion: h = vi_y * t - (1/2) * g * t^2 where h is the height, vi_y is the initial vertical velocity, t is the time, and g is the Show more…
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