A proton moves along a circular path in a region of a...

A proton moves along a circular path in a region of a uniform magnetic field. The magnetic field is directed into the plane of the page. The speed of the proton is 2.16 × 106 m/s and the magnetic field strength is 0.042 T. Charge of the proton is q=1.6 x 10-19 C. Mass of the proton is 1.67 x 10-27 kg. a. What is the magnitude of magnetic force on the proton? 2 pt b. What is direction of rotation of the proton along the circular path: clockwise or counterclockwise? (hint: apply right hand rule for magnetic force to determine direction of velocity) 1 pt c. For this proton determine, in m, the radius of the circular path. 2 pts

Transcript

00:01 In this question, they have given that we have a proton that is moving in a circular path with a velocity of 106 meter per second.

00:08 And the charge on the proton is equal to 1 .6, multiply by 10, ratio to the power minus 19 coulum.

00:14 And the magnetic field is given that is equal to 0 .04 to tesla.

00:18 Now, in the first part, we have to calculate the magnitude of magnetic force.

00:22 So, as we know, we always write the magnetic force is equal to q, multiply by v, cross, magnetic field so we will cross product of velocity and the magnetic field of the proton so according to this i can write q v b sine theta now in the question they have given that the magnetic field is into the plane of the page so my theta will be equal to 90 degree my theta will be equal to 90 degree so i can easily say that the force will be equal to only q v b so if i put the values in this formula so the q is given that is 1 .6 multiply by 10 raised to the power minus 19 column and the velocity is 106 meter per second and the magnetic field that is given 0 .042 tesla.

01:14 Now if i calculate this then the magnetic force will be equal to approximately 7 .12 multiply by 10 raise to the power minus 19 newton.

01:28 So this is the answer of the first part of this question that is the magnetic force is equal to 7 .12 multiply by 10 ratio the power minus 19 newton in the second part they have asked that what will be the direction of the velocity of the proton so let's say this is the circular path on which the proton is moving and they have given that the magnetic field is into the plane.

01:56 So according to the right hand thumb rule, we say that if we put our thumb in the direction of the velocity, so we can find the magnetic field direction from the curls.

02:10 So according to this, the magnetic field is into the plane.

02:15 So if i put my thumb into the plane direction, so i will find that the my finger, the curls of my finger will be moving in the clockwise direction...

Question

Please give Ace some feedback