A proton travels at $100 \mathrm{~m} / \mathrm{s}$ in and parallel to a $2.00-\mathrm{T}$ magnetic field. What is the magnitude of the force on the proton?
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6 \times 10^{-19} \, \text{C} \) (charge of a proton) - Velocity of the proton, \( V = 100 \, \text{m/s} \) - Magnetic field, \( B = 2.00 \, \text{T} \) - Angle between velocity and magnetic field, \( \theta = 0^\circ \) (parallel) ** Show more…
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