Question
A proton travels at $100 \mathrm{~m} / \mathrm{s}$ in and perpendicular to a $2.00-\mathrm{T}$ magnetic field. What is the magnitude of the force on the proton?
Step 1
The velocity of the proton (V) is given as $100 \mathrm{~m/s}$, the magnetic field (B) is given as $2.00 \mathrm{~T}$, and the charge of the proton (Q) is a known constant, $1.6 \times 10^{-19} \mathrm{~C}$. Show more…
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