A quantity of N2 occupies a volume of 1.0 L at 300 K and 1.0 atm. The gas expands to a volume of 3.0 L as the result of a change in both temperature and pressure. Find the density of the gas at these new conditions.
Added by Pamela O.
Step 1
0 atm V = 1.0 L T = 300 K R = 0.0821 L.atm/mol.K n = (P * V) / (R * T) n = (1.0 atm * 1.0 L) / (0.0821 L.atm/mol.K * 300 K) n = 0.04062 moles Show more…
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A quantity of $\mathrm{N}_{2}$ occupies a volume of $1.0 \mathrm{~L}$ at $300 \mathrm{~K}$ and $1.0 \mathrm{~atm}$. The gas expands to a volume of $3.0 \mathrm{~L}$ as the result of a change in both temperature and pressure. Find the density of the gas at these new conditions.
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