A quantum of thermal energy for aluminum is 4e-21 J. Using the quantum 3-D ball-spring (Einstein) model, calculate the number of ways to arrange 4 quanta of energy in a nanoparticle of aluminum that consists of 5 atoms. A. 56 B. 70 C. 3060 D. 816 E. 3876

Name: a quantum of thermal energy for aluminum is 4e21 j using the quantum 3 d ball spring einstein model calculate the the number of ways to arrange 4 quanta of energy in a nanoparticle of alumin 15943
Uploaded: 2022-05-05T09:23:51-08:00
Duration: 1 min 18 s
Channel: Adriano Chikande
Description: a quantum of thermal energy for aluminum is 4e21 j using the quantum 3 d ball spring einstein model calculate the the number of ways to arrange 4 quanta of energy in a nanoparticle of alumin 15943

          A quantum of thermal energy for aluminum is 4e-21 J. Using the quantum 3-D ball-spring (Einstein) model, calculate the number of ways to arrange 4 quanta of energy in a nanoparticle of aluminum that consists of 5 atoms.
A. 56
B. 70
C. 3060
D. 816
E. 3876

Added by Samantha A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adriano Chikande

05/05/2022

Step 1

Given: - Quantum of thermal energy for aluminum = 4e-21 J - Number of atoms in the nanoparticle = 5 - Number of quanta of energy = 4 Total number of energy quanta arrangements = (5*3)! / (4!*1!) = 60 Show more…

Show all steps

Thanks for your feedback!

A quantum of thermal energy for aluminum is 4e-21 J. Using the quantum 3-D ball-spring (Einstein) model, calculate the number of ways to arrange 4 quanta of energy in a nanoparticle of aluminum that consists of 5 atoms. A. 56 B. 70 C. 3060 D. 816 E. 3876