00:01
So we have a random sample from a normal distribution with mean 40 and standard deviation equal to 6.
00:14
After a treatment is administered to the individuals in the sample, we have a sample mean of 37 and we use sample size equal to 36.
00:30
And then we want to see if the treatment is effective or had a significant effect.
00:38
So our known hypothesis would be it has no effect, so the mean hasn't changed.
00:47
The mean is still 40.
00:49
And the alternative would be the mean has changed and that means the treatment had an effect.
00:57
So our sample statistic here then is we have normal, so we can use a z, which is x bar, which in this case is the capital m, minus mu divided by sigma over square root of n.
01:18
So this is 37 minus 40 divided by 6 over the square root of 36.
01:29
So this then is negative 3.
01:33
And we want to use alpha is 0 .05 and do a two -tail test.
01:41
So my critical region is plus or minus z alpha over 2, which is 0 .025, which is 25 % in detail, is positive or negative 1 .960.
02:07
So here we're gonna say our z is greater than z alpha over 2 because, oh, it's less than, we have negative, sorry.
02:26
We are less than negative z alpha over 2, negative 3 and negative 1 .960.
02:35
So if we were to draw this, my rejection region is 1 .960 and negative 1 .960.
02:45
So we're gonna reject anything in detail.
02:48
And our test statistic z is negative 3.
02:55
So that's definitely in the rejection region.
02:58
So conclusion, reject the null hypothesis.
03:06
Treatment has an effect or there is sufficient sufficient evidence to suggest, oops, that treatment has an effect.
03:34
So that was part one...