00:01
So in this question sample mean is given as, sample mean is given as 84 .6.
00:06
And sample standard deviation s is given as 20, small s.
00:12
Sample variation is going to be 400 and any sample size is given as 25.
00:18
So standard error of mean is going to be standard error of mean is going to be small s divided with under root end.
00:29
So this is going to be 4 approximately 4 value because we are dividing 20 divided with under root and 25.
00:36
So this is like under root 25.
00:39
So this is going to be 4.
00:40
So a point estimate of population mean mu is x bar equals to 84 .6.
00:49
So the critical point, critical value of t is going to be.
00:57
So the critical value of t is the critical value of t is the critical.
01:04
Value of t is going to be 1 .71 at this rate so this is going to be at 90 % interval the margin of error is going to be at 90 % confidence confidence confidence confidence interval the margin of error is going to be equal to s to as you added with under root n multiplied with t multiplied with critical value of t so this is going to be multiplied with t critical so this is going to be 20 divided with under root 25 multiplied with 1 .7 1 so this is going to be a standard error margin of error is going to be 6.
02:11
Approximately after calculation 6 .840 so a 90 % confident interval um of population mean is going to be at 90 % confidence interval the population mean is going to be the population mean mu is going to be x bar plus minus as under root n and the critical value of t which is going to be tc so we know that x bar is given as 74 .6 plus minus we have calculated it as 6 .840...