A rather flimsy spherical balloon is designed to pop at the instant its radius has reached 7 centimeters. Assuming the balloon is filled with helium at a rate of 16 cubic centimeters per second, calculate how fast the radius is growing at the instant it pops. (The volume of a sphere of radius r is V = (4/3)πr^3. Round your answer to two decimal places.)
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Step 1: Given that the volume of a sphere is V = (4/3)πr^3 and the rate of change of volume is dV/dt = 16 cm^3/s. Show more…
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