Question

A rock is dropped from the top of a vertical cliff and takes 3.00 s to reach the ground below the cliff. A second rock is thrown vertically from the cliff, and it takes this rock 2.00 s to reach the ground below the cliff from the time it is released. With what velocity was the second rock thrown, assuming no air resistance? 

          A rock is dropped from the top of a vertical cliff and takes 3.00 s to reach the ground below the cliff. A second rock is thrown vertically from the cliff, and it takes this rock 2.00 s to reach the ground below the cliff from the time it is released. With what velocity was the second rock thrown, assuming no air resistance?
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A rock is dropped from the top of a vertical cliff and takes 3.00 s to reach the ground below the cliff. A second rock is thrown vertically from the cliff, and it takes this rock 2.00 s to reach the ground below the cliff from the time it is released. With what velocity was the second rock thrown, assuming no air resistance?
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A rock is dropped from the top of a vertical cliff and takes 3.00 s to reach the ground below the cliff. A second rock is thrown vertically from the cliff, and it takes this rock 2.00 s to reach the ground below the cliff from the time it is released. With what velocity was the second rock thrown, assuming no air resistance?

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Transcript

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00:01 Hello students, so in this question we have a rock that is dropped from the top of a tower.
00:05 Ok, so we can draw the diagram.
00:07 So this is suppose the top of a tower.
00:10 Ok, this is ground and ball 1 suppose is dropped that is u equals to 0 and it take time t1 equals to 3 second to reach the bottom.
00:23 So let us suppose the height is h.
00:25 Now the second rock is thrown with velocity v and it take time 2 second.
00:32 Ok so we have to determine this velocity v.
00:37 Here first of all this height of the tower can be calculated from here...
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