00:01
In this problem we have given a roller coaster reached the top of the steepest hill with a speed v is equal to 61 km per hour.
00:11
So we will change it into meter per second by multiplying with 5 by 18.
00:17
So this is equal to 6 .1 into 5 by 18 that is equal to 1 .69 meter per second.
00:32
So suppose initially this is the roller coaster at the top of hill.
00:38
Initial speed is v initial which is equal to 1 .69 meter per second.
00:49
We have to find the speed of the roller coaster at the bottom of the hill.
00:55
So this angle theta is given to us which is equal to 35 degree.
01:06
In part a we have to find what will its speed when it reach the bottom.
01:13
So first of all we will try to find the acceleration of this roller coaster.
01:17
So the normal force will act in this direction, mg force will act in this direction, and friction force will act in this direction.
01:27
So there will be two component of mg force...