Question

A rollercoaster car is moving down a slope at 10 m/s at point A. Point A is 20.0 metres above the ground. It goes around a loop. At point B (the top of the loop) the car is moving at 15 m/s. What is the height of point B above the ground? Assume that frictional losses are negligible

Name: a rollercoaster car is moving down a slope at 10 ms at point a point a is 200 metres above the ground it goes around a loop at point b the top of the loop the car is moving at 15 ms what is the heig 2
Uploaded: 2021-11-06T16:08:18-08:00
Duration: 2 min 36 s
Channel: Ashwin Banarsee
Description: a rollercoaster car is moving down a slope at 10 ms at point a point a is 200 metres above the ground it goes around a loop at point b the top of the loop the car is moving at 15 ms what is the heig 2

          A rollercoaster car is moving down a slope at 10 m/s at point A. Point A is
20.0 metres above the ground. It goes around a loop. At point B (the top of the loop)
the car is moving at 15 m/s. What is the height of point B above the ground? Assume
that frictional losses are negligible

Added by Savisesh R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ashwin Banarsee

11/06/2021

Step 1

The kinetic energy (KE) at point A can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the rollercoaster car and v is its velocity. However, since we don't know the mass of the car, we can't calculate the exact kinetic energy. But we Show more…

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A rollercoaster car is moving down a slope at 10 m/s at point A. Point A is 20.0 metres above the ground. It goes around a loop. At point B (the top of the loop) the car is moving at 15 m/s. What is the height of point B above the ground? Assume that frictional losses are negligible