A rope moving at 30 m/s is in contact with a pulley of radius 0.5 m. What is the magnitude of the angular velocity of the pulley?
Added by Jose Antonio H.
Step 1
5 m, we can use the formula V = rω, where V is the linear velocity, r is the radius, and ω is the angular velocity. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Vysakh M and 72 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A fixed 0.15-kg solid-disk pulley with a radius of $0.075 \mathrm{~m}$ is acted on by a net torque of $6.4 \mathrm{~m} \cdot \mathrm{N}$. What is the angular acceleration of the pulley?
A frictionless pulley, which can be modeled as a $0.80 \mathrm{kg}$ solid cylinder with a $0.30 \mathrm{m}$ radius, has a rope going over it, as shown in Figure P7.48. The tension in the rope is $10 \mathrm{N}$ on one side and $12 \mathrm{N}$ on the other. What is the angular acceleration of the pulley?
Motor $M$ exerts a constant force of $P=750 \mathrm{N}$ on the rope. If the 100 -kg post is at rest when $\theta=0^{\circ}$ determine the angular velocity of the post at the instant $\theta=60^{\circ} .$ Neglect the mass of the pulley and its size, and consider the post as a slender rod.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
600,000+
Students learning Calculus with Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD