Question

A sample of steam with a mass of 0.535 g at a temperature of 100 °C condenses into an insulated container holding 4.20 g of water at 5.0 °C. (For water, ΔH°vap = 40.7 kJ/mol and Cwater = 4.18 J/(g⋅°C).) If no heat is lost to the surroundings, what is the final temperature of the mixture?

Name: a sample of steam with a mass of 0535 g at a temperature of 100 c condenses into an insulated container holding 420 g of water at 50 c for water hvap407 kjmol and cwater418 jgc if no heat is 03332
Uploaded: 2022-12-06T06:49:23-08:00
Duration: 2 min 3 s
Channel: Sri K
Description: a sample of steam with a mass of 0535 g at a temperature of 100 c condenses into an insulated container holding 420 g of water at 50 c for water hvap407 kjmol and cwater418 jgc if no heat is 03332

          A sample of steam with a mass of 0.535 g at a temperature of 100 °C condenses into an insulated container holding 4.20 g of water at 5.0 °C. (For water, ΔH°vap = 40.7 kJ/mol and Cwater = 4.18 J/(g⋅°C).)
If no heat is lost to the surroundings, what is the final temperature of the mixture?

Added by Victoria Y.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

12/06/2022

Step 1

Given: ΔH°vap = 40.7 kJ/mol = 40700 J/mol, mass of steam = 0.535 g Heat lost = 40700 J/mol * (0.535 g / 18 g/mol) = 1209.7 J Show more…

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A sample of steam with a mass of 0.535 g at a temperature of 100 °C condenses into an insulated container holding 4.20 g of water at 5.0 °C. (For water, ΔH°vap = 40.7 kJ/mol and Cwater = 4.18 J/(g⋅°C).) If no heat is lost to the surroundings, what is the final temperature of the mixture?