5 x 10^12 Bq),
- \( N \) is the number of atoms (4.0 x 10^{15} atoms).
Rearranging the formula to solve for λ gives:
\[ \lambda = \frac{A}{N} \]
Substituting the values:
\[ \lambda = \frac{3.5 \times 10^{12} \text{ Bq}}{4.0 \times 10^{15} \text{ atoms}}
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