This can be calculated using combinations, which is denoted as C(n, k) or "n choose k". In this case, n = 8 and k = 3, so we have:
C(8, 3) = $\frac{8!}{3!(8-3)!}$ = $\frac{8!}{3!5!}$ = $\frac{8\times7\times6}{3\times2\times1}$ = 56
Now, we need to find the
Show more…