0:00
Hi there.
00:01
So for this problem, we are given the output power.
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Output power.
00:11
And this is equal to 10 megawaps, which we can write as 10 times 10 to 6 watts.
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We are also given the efficiency and that we call ita, and that is 96 % that we can write as 0 .99%.
00:35
Sets.
00:37
And then with this information, we can obtain the input power.
00:43
So the input power is equal to the power output that we are given, and it is 10.
00:58
And this 10 times 10 to the 6, whaps divided by 0 .906.
01:06
So from this, we obtain a value of 10 .470.
01:11
Miga whaps.
01:14
So the total losses, the total losses, total losses in this problem is equal to the input power minus the output power.
01:32
So we substitute those values.
01:33
We will have that that is 10 .417 minus 10 mega whaps.
01:41
And then this will give us that the total losses are 0 .417 mega whaps.
01:50
So that's what we obtain for the total losses.
01:54
So now what we are going to do is to let, remember that in this problem, we are asked to estimate the purse phase value of resistance and inductance of the line.
02:08
So we're going to let art to be the resistance per se.
02:12
Phase resistance per phase.
02:20
That's one of the questions for this problem.
02:24
So using the output power, the phase, the, yes, the phase voltage that we are also given.
02:39
And the power factor, we can determine the current.
02:42
So for that, we use the following equation.
02:49
We know that the power is equal to the square root of three times the phase voltage times the current phase and this times the cosine of fee.
03:01
The cosine of fee we know because the cosine of fee is the information that we are given about 0 .8 lag in power.
03:13
So this has a value of 0 .8.
03:16
The phase voltage is the value that we are told that is 30 kilo bolts at the receiving end.
03:25
And so this is 30, that we can write as 30 times 10 to the three bowls.
03:33
And finally, we know the power is 10 megawatts.
03:37
So solving for the current, we obtained the current in here, is the power, which is 10 times 10 to the 6 watts because it is mega.
03:51
And this divided by the square root of three times the voltage, which is 30 times 10 to the 3 bulls, and this times the cosine of c, which is the login, which is 0 .8...