00:01
Hello guys, let's get started with the solution.
00:05
The given data in the question is, edge length of silver is 2 .31 centimeter, while the edge length of gold is 2 .79 centimeter.
00:34
Initial temperature of silver and gold is 84 .4 degrees celsius.
00:48
Volume of water is 109 .5m as density of water is 1 gram per eml therefore mass of water would be 109 .5 gram now initial temperature of water is 19 .6 degrees celsius so first of all let find the volume of silver a cube it would be 2 .3 1 whole cube similarly volume of gold equals a cube equals 2 .79 whole cube upon solving the value would be around 12 .326 centimeter cube and here it would be 21 .717 centimeter cube.
01:53
So from the volume we are also provided with the densities the density of silver is 12 10 .5 gram per centimeter cube.
02:07
Well, density of gold is 19 .3 gram per centimeter cube hence we can find the mass of silver volume times density equals 12 .326 centimeter cube times 10 .5 gram per centimeter cube common unit will cancel each other similarly mass of gold equals volume times density 21 .717 centimeter cube times 19 .3 gram per centimeter cube.
02:47
Common units will cancel each other upon solving the numbers the value would be around 129 .423 gram and here it would be 419 .138 gram so we have found the mass here now we know that at thermal equilibrium heat lost is equal to heat gained.
03:29
Therefore, the amount lost by the metals would be equal to the amount of heat gained by the water.
03:38
So this would be q -a -g plus q -g -plus q -gold equals minus of q water.
03:49
Now, we know that here heat change can be represented as m -c -a -g -d -t -t plus m, c, a, u, delta, t, where c is the heat capacity of the respective species equals mcw, heat capacity of water, delta t.
04:15
So, m, a, g, we can represent the mass in terms of the respective species as well.
04:26
M, a, g, c, a, g, delta t is t f minus ti, plus m, a .g, a, u.
04:40
C -a -u t -f -m -t -r equals minus m -w -c -w t -f -m -t -i.
04:55
Now, we can write it as m -a -g -g -t -f -f -m -a -g -g -t -f -i -t -i -r plus m -a -g -a -u -c -a -u -t -f minus m -a -u -c -a -u -t -i -i -e -i -i -e -i -e -f -s -w -t -i -s -s -w -t -i.
05:58
So we will take t -f common from the t -f side...