00:01
Here we wish to prove that any simple graph with n greater than equal to two vertices has at least two vertices of equal degree.
00:17
Now for this firstly consider a graph g such that it is a finite simple graph with more than one vertex.
00:31
So, g has more than one vertex.
00:38
And also note that the degree of v is equal to n is greater than equal to 2.
00:48
So, firstly we will notice that the maximum degree, let us say md of any vertex in g is less than equal n.
01:04
So, maximal degree here found is less than equal n minus 1.
01:17
Also, if our graph g is not connected, then we have the maximal degree, that is md, is strictly, note that the word strictly.
01:36
Less than n minus 1.
01:40
Now we will form two cases to solve this problem.
01:44
The first case will be if the graph g is connected.
01:50
Now in this case we cannot have a vertex of degree 0 in g.
01:57
So degree zero vertex in g not there...