A skydiver jumps from an airplane. The distance she falls (in feet) is given by the function $f(t) = 16t^2$ where $t$ is the time elapsed since she jumped out of the airplane. Find her average speed (i.e., average rate of change of distance) from $t = 2$ to $t = 5$.
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Using the function f(t) = 16t^2, we can calculate: f(2) = 16(2)^2 = 16(4) = 64 feet f(5) = 16(5)^2 = 16(25) = 400 feet Show more…
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