00:01
Find the stress in the steel rod.
00:02
Now, in our problem, our deflection is going to be the same for both bars.
00:07
So we can write an expression that fs, our deflection in steel, is our diameter of steel squared, e of steel, over db squared minus db squared, eb times fb.
00:23
And so this will be our diameter of steel, 40 squared, times 200 kiloons, or times for steel, e is 206, so 206, divide that by our 60 squared minus 40 squared times e for bronze, which is 96, and this will be fb.
00:50
Now let's plug this into a calculator.
00:53
We're going to have our 40 squared times 206 divided by 60 squared minus 40 squared, all of that times 96.
01:10
And so that will be 1 .716 times fb.
01:15
But now we can find the load shared by each bar.
01:18
We can write 1 .716 fb plus fb is equal to f.
01:25
So fb is just our 200, divide that by 2 .716...