00:01
So we are given this situation.
00:03
Okay, first of all, the torque about this point o, the point of rotation is equal to what? it is equal to r cross f and the angle between r vatine and f is 90.
00:12
So it would be rf, so that means 0 .15 times 50.
00:17
This is the torque applied.
00:18
So now let's find out this value.
00:20
So that means 0 .15 times 50 and the answer is 7 .5.
00:25
So torque applied is equal to 7 .5 meters meter.
00:28
We all know that as for the newton's second law, net torque is equal to moment of inertia times alpha, angular acceleration.
00:36
So moment of inertia would be torque divided by angular acceleration, alpha.
00:39
That means 7 .5 divided by alpha, and the value of alpha we have is equal to 110...