00:01
For this problem, we want to find the volume of the solid, which is a circular base of radius 3, and that the cross -sections, perpendicular to the base, are squares.
00:10
If we are to illustrate this, we have this circular base of radius 3, and then cross -sections perpendicular to the base are squares, so we'll draw v squares.
00:22
So the volume, if we're dealing with cross -sections, it'll be v -equal to the integral from a to b, of the area of the cross -section and then dx.
00:35
So in here, if this is the squares that we have, note that the length of the set of the square is equal to 2y.
00:47
Because from the x -axis to this point, that's y, and then from this point to this point, that's also y...