00:01
The question is asking to determine the smallest stress divider of the shaft.
00:04
First, let us say the given data given, the power p given, 20 kilowatt, free per cent, f given, who has the shear stress, tau should not exist exceed 40 megapascal.
00:21
Anglia which is limited to 60 degrees.
00:24
Length is, let us represent capital, points three meter, given, capital g, given, 83 giga pascal, we know omega is equal to 2 pi f so on subtraction about it we get 2 pi multiplied by f value 2 we get so finally 4 pi radian per 7 we also know the relation power p is equal to t omega on sub string again the torque t we get b divided by omega the value 20 types and power 3 divided by 4 pi radian per 7 our further simplification we get 1591 .51 .55 neuterometer.
01:11
Now we got the torque value.
01:14
We know the relation t divided by j is equal to g theta divided by l is equal to devoured by r...