a solution of Na2CO3 is prepared by dissolving 0.21g of sodium carbonate and diluting to 100ml. calculate the normality: if it is used as a monobasic acid
Added by Bella M.
Step 1
First, we need to calculate the number of moles of Na2CO3. The molar mass of Na2CO3 is approximately 105.99 g/mol. So, 0.21g of Na2CO3 is 0.21g / 105.99 g/mol = 0.00198 mol. Show more…
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