A solution of Na2S2O3 (FW=158.11) was standardized with 25.00 mL 0.01150 M KIO3 (FW = 214.01). 25 mL of distilled water, 2.0 g of solid KI and 10 mL of 0.100 M H2SO4 were added to liberate 12. The liberated 12 required 18.05 mL Na2S2O3 to reach the pale yellow solution after which starch was addedIt took additional 2.50 mL of the titrant for the blue color disappears. Calculate the molarity of Na2S2O3.