00:01
Hello students, here in this question from the given data of sucrose first of all we have to find out the molality.
00:06
Molality is equal to number of moles of solute divided by mass of solution in kilogram.
00:11
First of all we can find out the mass of sucrose by multiplying the density with volume.
00:15
Density is given as 1 .08 gram per ml and the volume is taken as 1000 ml and we will get the mass as 1080 gram in kilogram it is 1 .080 kilogram.
00:28
So here we can find out the molality.
00:31
So the molality here will be equal to the number of moles will be equal to 0 .02 into molar into volume 1 liter divided by the mass of solution is 1 .080 as a result here we will get the molality as 0 .0185 molar.
00:50
Next we have to find out the mole fraction.
00:53
Mole fraction is equal to number of moles of sucrose divided by the total number of moles of solute.
00:58
So here mole fraction here will be equal to the number of moles of sucrose is 0 .02 molar into 1 liter divided by total number of moles is also 0 .02 molar into 1 liter that is as a result here we will get the fraction value as 1.
01:18
Next we have to find out the percentage by mass...