A sucrose solution is prepared by dissolving 18.50 g of sucrose (C12H22O11) in 150 g of water. What is the molality of the sucrose solution? [Molar mass (g/mol): C12H22O11 = 342.3 and H2O = 18.02] a. 0.17m b. 0.36m c. 0.56m d. 0.0228m
Added by Nathan F.
Step 1
We can do this by dividing the mass of sucrose by its molar mass: Moles of sucrose = (18.50 g) / (342.3 g/mol) = 0.0540 mol Show more…
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