By dissolving 50.4 g of sucrose (C12H22O11) in 0.332 kg of water, a solution with a volume of 355 mL was formed. Calculate each of the following terms: a. molarity of the solution b. mole fraction of sucrose c. mass percent sucrose
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Step 1
Given: Mass of sucrose (C12H22O11) = 50.4 g Molar mass of sucrose (C12H22O11) = 342.3 g/mol Volume of solution = 355 mL = 0.355 L Moles of sucrose = Mass of sucrose / Molar mass of sucrose Moles of sucrose = 50.4 g / 342.3 g/mol Moles of sucrose = 0.147 Show more…
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