Question

A spacecraft is traveling with a velocity of v0x = 5360 m/s along the +x direction. Two engines are turned on for a time of 717 s. One engine gives the spacecraft an acceleration in the +x direction of ax = 1.34 m/s2, while the other gives it an acceleration in the +y direction of ay = 7.38 m/s2. At the end of the firing, what is a) vx and b) vy?

Name: a spacecraft is traveling with a velocity of v0x 5360 ms along the x direction two engines are turned on for a time of 717 s one engine gives the spacecraft an acceleration in the x directio 18672
Uploaded: 2022-06-06T16:24:48-08:00
Duration: 2 min 54 s
Channel: Sri K
Description: a spacecraft is traveling with a velocity of v0x 5360 ms along the x direction two engines are turned on for a time of 717 s one engine gives the spacecraft an acceleration in the x directio 18672

          A spacecraft is traveling with a velocity of v0x = 5360 m/s
along the +x direction. Two engines are turned on for a time of 717
s. One engine gives the spacecraft an acceleration in the +x
direction of ax = 1.34 m/s2, while the other gives it an
acceleration in the +y direction of ay = 7.38 m/s2. At the end of
the firing, what is a) vx and b) vy?

Added by Mary R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

06/06/2022

Step 1

34 \, \text{m/s}^2\) Time, \(t = 717 \, \text{s}\) Using the equation of motion \(v_x = v_{0x} + a_x \cdot t\), we can find the final velocity in the X direction: \[v_x = 5360 + 1.34 \times 717\] \[v_x = 5360 + 959.38\] \[v_x = 6319.38 \, \text{m/s}\] Show more…

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A spacecraft is traveling with a velocity of v0x = 5360 m/s along the +x direction. Two engines are turned on for a time of 717 s. One engine gives the spacecraft an acceleration in the +x direction of ax = 1.34 m/s2, while the other gives it an acceleration in the +y direction of ay = 7.38 m/s2. At the end of the firing, what is a) vx and b) vy?