A spring has a natural length of 10 in. An 800 -lb force stretches the spring to 14 in. (a) Find the force constant. (b) How much work is done in stretching the spring from 10 in. to 12 in.? (c) How far beyond its natural length will a 1600 -lb force stretch the spring?
Added by Derrick H.
Step 1
Given: Force (F) = 800 lb Extension (x) = 14 in - 10 in = 4 in Plugging in the values: 800 lb = k * 4 in k = 800 lb / 4 in k = 200 lb/in Therefore, the force constant is 200 lb/in. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Suman Saurav Thakur and 54 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A spring has a natural length of 10 in. An 800-lb force stretches the spring to 14 in. a. Find the force constant. b. How much work is done in stretching the spring from 10 in. to 12 in.? c. How far beyond its natural length will a 1600-lb force stretch the spring?
Adi S.
Stretching a Spring A spring has a natural length of 10 in. An 800 -lb force stretches the spring to 14 in. (a) Find the force constant. (b) How much work is done in stretching the spring from 10 in. to 12 in.? (c) How far beyond its natural length will a 1600 -lb force stretch the spring?
Applications of Definite Integrals
Applications from Science and Statistics
To stretch a spring 3.00 cm from its unstretched length, 12.0 J of work must be done. (a) What is the force constant of this spring? (b) What magnitude force is needed to stretch the spring 3.00 cm from its unstretched length? (c) How much work must be done to compress this spring 4.00 cm from its unstretched length, and what force is needed to compress it this distance?
Work and Kinetic Energy
Work and Energy with Varying Forces
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD