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Hello everyone.
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So here in this question it is given that there is a spring and spring constant is given as two multiplied by 10 to the part three.
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Value of x is given as 0 .55 meters.
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Mass of the block is 2 .5 kg.
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We have to calculate the velocity just after leaving the spring after compressing it.
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So we can use energy conservation here that half kx square is equals to half m v square.
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So from here we can say that v is equals to x under root k divided by m.
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So as we know value of x is 0 .55 under root, value of k is 2 multiplied by 10 to be power 3 and value of m is 2 .4.
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So we can write it as 0 .55 under root 2 multiplied by, if we will remove decimal from here, it will add on here.
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So we can write it as 400.
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So on solving this, velocity will come out to be 15 .84 meter per second.
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So this is the velocity.
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Now in the next question, it is asked that if at the end when velocity will be zero, what will be the distance? it will travel.
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What will be the distance? it will travel if it is a friction surface.
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If it is via rough surface.
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So we can say that half mv1 square will convert it into mgh plus mu mgm...