Question

A square loop of wire of edge length $a$ carries current $i$. Show that, at the center of the loop, the magnitude of the magnetic field produced by the current is $$ B=\frac{2 \sqrt{2} \mu_{0} i}{\pi a} $$

          A square loop of wire of edge length $a$ carries current $i$. Show that, at the center of the loop, the magnitude of the magnetic field produced by the current is
$$
B=\frac{2 \sqrt{2} \mu_{0} i}{\pi a}
$$

Added by Janet G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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A square loop of wire of edge length $a$ carries current $i$. Show that, at the center of the loop, the magnitude of the magnetic field produced by the current is $$ B=\frac{2 \sqrt{2} \mu_{0} i}{\pi a} $$