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Hi there.
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So for this problem, we are told that a steel belted radial automobile tire is inflated to a gauge pressure.
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So we're going to call this the gauge pressure 1 is equal to 1 .85 times 10 to the 5 pascal.
00:23
And when the temperature is a temperature that we're going to call temperature 1 of 69 fahrenheit degrees, and the temperature 2, the problem states that later in the date the temperature rises to a value of 96 fahrenheit degrees.
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And we're also told that what we need to calculate is assuming that the volume is of star is constant, volume constant.
00:57
And we need to calculate the gauge pressure at the elevated temperature.
01:03
So we need to calculate the gate pressure 2.
01:07
So the first thing that we are going to do is to transform the temperatewards from hurricane to kelvin.
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So 69 fahrenheit to kelvin, 69 is equal to 293 .0 .9 kelvin and 96 .0 .000.
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Is equal to 308 .7 kelvin.
01:47
So what we are going to use in this case is the following equation.
01:52
That is that the pressure one, in this case, is the absolute pressure.
01:56
So we need to transform the values that we have engaged pressure to absolute pressure, divided up by the temperature 1 is equal to the absolute pressure 2 divided by the temperature 2.
02:06
As the parliament states, you need to remember that the ideal cost law uses the absolute pressure, as you can see in here.
02:15
Now, the absolute pressure one is simply the gauge pressure given one plus the atmospheric pressure that we call p .0.
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Now, that is going to be 1 .85 times 10 to the 5 pascal.
02:37
That is the value given for the gauge pressure.
02:42
And this plus the atmospheric pressure that we know is 1 .013 times 10 to the 5 pascal.
02:50
So from this, we obtained that the absolute pressure 1 is equal to 2 .863 times...