Question

A steel control rod is 5.5 ft long and must not stretch more than 0.04 in. when a 2 -kip tensile load is applied to it. Knowing that $E=29 \times 10^{6} \mathrm{psi},$ determine $(a)$ the smallest diameter rod that should be used, ( $b$ ) the corresponding normal stress caused by the load.

Name: A steel control rod is 5.5 ft long and must not stretch more than 0.04 in. when a 2 -kip tensile load is applied to it. Knowing that E=29 × 10^6psi, determine (a) the smallest diameter rod that should be used, ( b ) the corresponding normal stress caused by the load.
Uploaded: 2021-11-15T11:13:45-08:00
Duration: 3 min 24 s
Channel: Vaidik Stats
Description: A steel control rod is 5.5 ft long and must not stretch more than 0.04 in. when a 2 -kip tensile load is applied to it. Knowing that E=29 × 10^6psi, determine (a) the smallest diameter rod that should be used, ( b ) the corresponding normal stress caused by the load.

          A steel control rod is 5.5 ft long and must not stretch more than 0.04 in. when a 2 -kip tensile load is applied to it. Knowing that $E=29 \times 10^{6} \mathrm{psi},$ determine $(a)$ the smallest diameter rod that should be used, ( $b$ ) the corresponding normal stress caused by the load.

Added by Kim U.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vaidik Stats

11/15/2021

Step 1

The length of the rod is given as 5.5 ft, which needs to be converted to inches since the elongation is given in inches. \[ 5.5 \, \text{ft} = 5.5 \times 12 \, \text{in} = 66 \, \text{in} \] Show more…

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A steel control rod is 5.5 ft long and must not stretch more than 0.04 in. when a 2 -kip tensile load is applied to it. Knowing that $E=29 \times 10^{6} \mathrm{psi},$ determine $(a)$ the smallest diameter rod that should be used, ( $b$ ) the corresponding normal stress caused by the load.