00:01
So to find the weight of the wire for part a, we know that the weight of the wire is going to be equal to the proportionality limit of wire times the young's modulus of the wire times the cross -sectional area of the wire.
00:16
So the weight is going to be equal to 0 .0016 times the young's modulus.
00:22
So 20 times 10 to the 10th pascal's times the area.
00:27
So 0 .05 times 10 to the negative 4th.
00:33
Meters squared, and this is equaling 1 ,600 newtons.
00:40
So that would be the weight.
00:41
And then for part b, when they're asking us for the elongation, we can say that the elongation is the change in length.
00:48
This would be equal to the force divided by the area times the original length divided by the young's modulus.
00:54
So this would be equal to the force.
00:57
We can say 0 .05 times 10 to the negative 4 meters squared, times.
01:06
Times 20 times 10 to the 10th pascal's.
01:11
And then for the force, again, 1 ,600 newtons, it would simply be the weight...